head	1.4;
access;
symbols
	pkgsrc-2026Q2:1.4.0.8
	pkgsrc-2026Q2-base:1.4
	pkgsrc-2026Q1:1.4.0.6
	pkgsrc-2026Q1-base:1.4
	pkgsrc-2025Q4:1.4.0.4
	pkgsrc-2025Q4-base:1.4
	pkgsrc-2025Q3:1.4.0.2
	pkgsrc-2025Q3-base:1.4
	pkgsrc-2025Q2:1.3.0.4
	pkgsrc-2025Q2-base:1.3
	pkgsrc-2025Q1:1.3.0.2
	pkgsrc-2025Q1-base:1.3;
locks; strict;
comment	@# @;


1.4
date	2025.08.13.11.06.33;	author pho;	state Exp;
branches;
next	1.3;
commitid	oGqtJTKdyCfCKy6G;

1.3
date	2025.03.05.03.39.05;	author pho;	state Exp;
branches;
next	1.2;
commitid	VPkRDaZT4MoYrPLF;

1.2
date	2025.02.02.13.05.00;	author pho;	state Exp;
branches;
next	1.1;
commitid	Zl7FwsffomOQzTHF;

1.1
date	2025.01.31.02.51.23;	author pho;	state Exp;
branches;
next	;
commitid	xt3FqhIhbsjEfAHF;


desc
@@


1.4
log
@Bump all Haskell because lang/ghc910 has got a library change
@
text
@# $NetBSD: Makefile,v 1.3 2025/03/05 03:39:05 pho Exp $

DISTNAME=	choice-0.2.4.1
PKGREVISION=	3
CATEGORIES=	devel

MAINTAINER=	pkgsrc-users@@NetBSD.org
COMMENT=	Solution to boolean blindness
LICENSE=	public-domain

.include "../../mk/haskell.mk"
.include "../../mk/bsd.pkg.mk"
@


1.3
log
@recursive revbump after patching lang/ghc910
@
text
@d1 1
a1 1
# $NetBSD: Makefile,v 1.2 2025/02/02 13:05:00 pho Exp $
d4 1
a4 1
PKGREVISION=	2
@


1.2
log
@Bump all Haskell packages after switching the default compiler.
@
text
@d1 1
a1 1
# $NetBSD: Makefile,v 1.1 2025/01/31 02:51:23 pho Exp $
d4 1
a4 1
PKGREVISION=	1
@


1.1
log
@devel/hs-choice: import hs-choice-0.2.4.1

Represent do/don't, is/isn't, with/without flags with Choice.

Boolean blindness
(https://existentialtype.wordpress.com/2011/03/15/boolean-blindness) refers
to the problem that boolean literals on their own aren't very
informative. In any given context, what does True mean? What does False
mean? Instead of passing arguments of type Bool to functions, consider
using Choice.
@
text
@d1 1
a1 1
# $NetBSD$
d4 1
@